Class 11 Physics Numericals for Beginners – 20 Solved Questions Step by Step

Class 11 Physics • NCERT • Beginner Practice

Class 11 Physics Numericals for Beginners – 20 Solved Questions Step by Step

Understand Physics formulas with 20 easy numerical questions, clear calculations, SI units, practical examples and simple explanations for Class 11 students.

20 Solved Numericals Easy Formulas Step-by-Step Solutions NCERT Concepts Physics Revision

Class 11 Physics becomes difficult for many students because the subject is quite different from Class 10 Science. Suddenly, there are more formulas, vectors, motion graphs, forces and calculations. Even students who understand the theory often get confused when a numerical question appears.

You may know the formula for acceleration, but when a question gives initial velocity, time and final velocity together, choosing the correct method becomes confusing. Sometimes the formula is correct but the final answer is wrong because kilometres were not converted into metres or the unit was forgotten.

That is why practising Physics numericals from the basic level is important. Instead of memorising every solved example, students should learn how to identify the given values, choose a formula and solve the question carefully.

This guide includes 20 Class 11 Physics numericals for beginners from different chapters. Every question follows a simple process so you can understand the calculation without feeling lost.

How to solve Physics numericals: Read the question carefully, write the given values, convert them into SI units, choose the correct formula, substitute the values and write the final answer with its unit.

If a chapter itself feels difficult, understand the concept before solving its questions. You can explore the best YouTube channels for Class 11 Physics for lectures that explain motion, forces, energy and numerical-solving methods.

How to Solve Class 11 Physics Numericals Easily

Class 11 Physics Numericals for Beginners – 20 Solved Questions Step by Step

Before starting the solved questions, remember one simple thing: Physics numericals are easier when you solve them in a fixed order.

Given Values → SI Units → Formula → Substitution → Final Answer

Suppose a car travels 100 metres in 20 seconds. You need to calculate its average speed. First identify distance and time, then use the speed formula.

Average Speed = Total Distance / Total Time
Average Speed = 100 / 20 = 5 m/s

This is the same basic method that we will use throughout the following questions.

Common SI Units Used in Physics

Quantity SI Unit Symbol
Lengthmetrem
Masskilogramkg
Timeseconds
Speedmetre per secondm/s
Accelerationmetre per second squaredm/s²
ForcenewtonN
Work and EnergyjouleJ
PowerwattW
PressurepascalPa
FrequencyhertzHz

Class 11 Science students also need regular practice in Maths and Chemistry. If you are arranging free learning resources for all three subjects, the Class 11 subject-wise YouTube study guide can help you organise your study routine.

Units and Measurements – Solved Numericals (1–2)

Units and Measurements is a useful starting chapter because every numerical in Physics depends on correct units. Learn conversions and dimensions before moving towards longer calculations.

Question 1: Convert km/h into m/s

A car is moving at 90 km/h. Convert its speed into metres per second.
Given: Speed = 90 km/h

Formula:

Speed in m/s = Speed in km/h × 5/18
  1. Write the given speed: 90 km/h.
  2. Multiply by 5/18 to convert the unit.
  3. 90 × 5/18 = 25.
Final Answer: 25 m/s

Easy explanation: One kilometre equals 1000 metres and one hour equals 3600 seconds. Therefore, multiplying by 1000/3600, or 5/18, converts km/h into m/s.

Question 2: Find the Dimensional Formula of Force

Using Newton's second law, find the dimensional formula of force.
Given: Force = Mass × Acceleration

Formula:

F = ma
  1. Dimension of mass = [M].
  2. Dimension of acceleration = [LT⁻²].
  3. Multiply the dimensions of mass and acceleration.
[F] = [M] × [LT⁻²] = [MLT⁻²]
Final Answer: [MLT⁻²]

This shows that the dimensions of force contain one power of mass, one power of length and minus two powers of time.

Motion in a Straight Line and Plane – Numericals (3–9)

Motion is one of the most useful chapters for learning Physics calculations. The questions usually involve speed, velocity, acceleration, distance, displacement and time.

Always check whether a question asks for distance or displacement. Distance measures the total path travelled, while displacement depends on the change in position and direction.

Question 3: Calculate Average Speed

A student cycles a total distance of 600 metres in 120 seconds. Find the average speed.
Given: Distance = 600 m, Time = 120 s
Average Speed = Total Distance / Total Time
  1. Write the distance as 600 m.
  2. Write the time as 120 s.
  3. Divide 600 by 120.
Average Speed = 600/120 = 5 m/s
Final Answer: 5 m/s

Question 4: Calculate Average Velocity

A student walks 80 metres east and then 30 metres west. The complete journey takes 25 seconds. Find the average velocity.
Understanding the Direction of Motion
80 m East → ← 30 m West

First move east, then return part of the distance west. East is taken as the positive direction.

Given: Eastward movement = +80 m, Westward movement = −30 m, Time = 25 s
  1. Calculate net displacement: 80 − 30 = 50 m east.
  2. Use average velocity = displacement / time.
  3. Substitute: 50/25 = 2.
Final Answer: 2 m/s towards East

Remember: The total distance is 110 m, but displacement is only 50 m east. This is why average speed and average velocity are different.

Question 5: Final Velocity and Displacement

A body starts with a velocity of 3 m/s and accelerates uniformly at 2 m/s² for 5 seconds. Find its final velocity and displacement.
Given: u = 3 m/s, a = 2 m/s², t = 5 s

Part A: Final Velocity

v = u + at
  1. Substitute the values: v = 3 + (2 × 5).
  2. Calculate: v = 3 + 10.
  3. Final velocity = 13 m/s.

Part B: Displacement

s = ut + ½at²
  1. s = (3 × 5) + ½ × 2 × 5².
  2. s = 15 + 25.
  3. Displacement = 40 m.
Final Answer: Velocity = 13 m/s, Displacement = 40 m

Question 6: Braking Distance of a Car

A car is travelling at 20 m/s. Its brakes produce a uniform deceleration of 4 m/s². Find the time and distance required to stop.
Given: u = 20 m/s, v = 0, a = −4 m/s²

Step 1: Find stopping time.

v = u + at
0 = 20 − 4t
t = 20/4 = 5 s

Step 2: Find stopping distance.

s = ut + ½at²
s = (20 × 5) + ½(−4)(5²)
s = 100 − 50 = 50 m
Final Answer: Stopping Time = 5 s, Stopping Distance = 50 m

Common mistake: Deceleration is negative when the positive direction is the initial direction of motion.

Question 7: Velocity-Time Graph Numerical

The velocity of a body increases uniformly from 2 m/s to 14 m/s in 4 seconds. Find acceleration and displacement.
Given: u = 2 m/s, v = 14 m/s, t = 4 s

Part A: Acceleration

a = (v − u)/t
a = (14 − 2)/4 = 3 m/s²

Part B: Displacement

For uniform acceleration, displacement equals average velocity multiplied by time. It is also the area under the velocity-time graph.

s = [(u + v)/2] × t
s = [(2 + 14)/2] × 4 = 32 m
Final Answer: Acceleration = 3 m/s², Displacement = 32 m

Question 8: Resultant of Two Perpendicular Forces

Two forces of 6 N east and 8 N north act at the same point. Find the magnitude of the resultant force.
Given: F₁ = 6 N, F₂ = 8 N, Angle between forces = 90°

Because the forces are perpendicular, we can use Pythagoras' theorem.

R = √(F₁² + F₂²)
  1. Square the first force: 6² = 36.
  2. Square the second force: 8² = 64.
  3. Add: 36 + 64 = 100.
  4. Find √100 = 10.
Final Answer: Resultant Force = 10 N

This result gives the magnitude. The resultant direction lies between east and north.

Question 9: Projectile Motion

A ball is projected at 20 m/s at an angle of 30° above the horizontal. Find its time of flight, maximum height and range. Take g = 10 m/s² and ignore air resistance. Assume it lands at the same height.
Given: u = 20 m/s, θ = 30°, g = 10 m/s², sin 30° = 0.5

Step 1: Vertical component.

uᵧ = u sin θ = 20 × 0.5 = 10 m/s

Step 2: Time of flight.

T = 2uᵧ/g = (2 × 10)/10 = 2 s

Step 3: Maximum height.

H = uᵧ²/(2g)
H = 10²/(2 × 10) = 5 m

Step 4: Horizontal range.

The horizontal component is uₓ = 20 cos 30° ≈ 17.32 m/s.

Range = uₓ × T = 17.32 × 2
Final Answer: Time = 2 s, Maximum Height = 5 m, Range ≈ 34.64 m

Remember: For a projectile launched and landing at the same height, the total time of flight is twice the time taken to reach the highest point.

Motion and forces form an important foundation for students planning engineering entrance preparation. Once these basics are clear, our JEE Mechanics learning guide can help you move towards more detailed problems in Kinematics, Newton's Laws and Rotation.

Laws of Motion – Solved Numericals (10–12)

Newton's laws explain how forces affect the motion of objects. In numericals, students usually need to calculate force, friction, momentum or impulse.

Question 10: Calculate Force

A body of mass 5 kg accelerates at 3 m/s². Find the net force acting on it.
Given: m = 5 kg, a = 3 m/s²
F = ma
  1. Write the mass: 5 kg.
  2. Write acceleration: 3 m/s².
  3. Multiply mass by acceleration.
F = 5 × 3 = 15 N
Final Answer: Net Force = 15 N

Concept: Newton's second law relates the net external force on an object to its acceleration.

Question 11: Frictional Force

A 10 kg block is sliding on a horizontal surface. The coefficient of kinetic friction is 0.2. Find the frictional force. Take g = 10 m/s².
Forces on a Block on a Horizontal Surface
↑ Normal Reaction
← Friction
10 kg
Motion →
↓ Weight (mg)

Illustration: Friction acts opposite to the relative sliding motion.

Given: m = 10 kg, μ = 0.2, g = 10 m/s²

On a horizontal surface with no other vertical force, the normal reaction is mg.

N = mg = 10 × 10 = 100 N
fₖ = μN
fₖ = 0.2 × 100 = 20 N
Final Answer: Frictional Force = 20 N

Common mistake: The coefficient of friction has no unit. Frictional force is measured in newtons.

Question 12: Impulse and Change in Momentum

A ball of mass 0.5 kg changes its velocity from 2 m/s to 6 m/s in the same direction. Find the impulse acting on it.
Given: m = 0.5 kg, u = 2 m/s, v = 6 m/s

Formula:

Impulse = Change in Momentum
J = m(v − u)
  1. Find change in velocity: 6 − 2 = 4 m/s.
  2. Multiply by mass: 0.5 × 4.
Final Answer: Impulse = 2 N·s

An impulse of 2 N·s is equivalent to a momentum change of 2 kg·m/s.

When you start solving more numericals, it helps to maintain a notebook for formulas and common mistakes. The short-notes and revision guide explains how to organise formulas and important concepts without copying entire chapters.

Work, Energy and Power – Numericals (13–15)

Work, Energy and Power is easier to understand when you connect formulas with daily activities. Pushing a box, lifting an object and running a machine are familiar examples of these concepts.

Question 13: Calculate Work Done

A constant horizontal force of 20 N moves a box 3 metres in the direction of the force. Find the work done.
Given: F = 20 N, s = 3 m, Angle = 0°
W = Fs cos θ

Since cos 0° = 1:

W = 20 × 3 × 1 = 60 J
Final Answer: Work Done = 60 J

Work done is positive because the force and displacement point in the same direction.

Question 14: Kinetic Energy of a Moving Object

A body has a mass of 4 kg and is moving at 5 m/s. Calculate its kinetic energy.
Given: m = 4 kg, v = 5 m/s
KE = ½mv²
  1. Square the speed: 5² = 25.
  2. Multiply by mass: 4 × 25 = 100.
  3. Divide by 2.
KE = ½ × 4 × 25 = 50 J
Final Answer: Kinetic Energy = 50 J

Remember: Kinetic energy depends on the square of speed. If speed doubles while mass remains constant, kinetic energy becomes four times as large.

Question 15: Calculate Power

A machine performs 360 joules of work in 12 seconds. Find its average power.
Given: Work = 360 J, Time = 12 s
Average Power = Work / Time
P = 360/12 = 30 W
Final Answer: Average Power = 30 W

Power tells us how quickly work is done. One watt means one joule per second.

Rotation, Gravitation, Fluids, Heat and Waves (16–20)

Once you understand the earlier formulas, the same step-by-step method can be used in other chapters. Some formulas are new, but the solving process remains familiar.

Question 16: Torque in Rotational Motion

A perpendicular force of 15 N acts at a distance of 0.4 metres from the axis of rotation. Find the torque.
Given: F = 15 N, r = 0.4 m, Angle = 90°
τ = rF sin θ

Since the force acts perpendicular to the position vector, sin 90° = 1.

τ = 0.4 × 15 × 1 = 6 N·m
Final Answer: Torque Magnitude = 6 N·m

Easy explanation: Torque describes the turning effect of a force. For example, a door is easier to open when you push near the handle instead of near the hinges.

Question 17: Gravity at Twice the Earth's Radius

The acceleration due to gravity at Earth's surface is 10 m/s². Find its value at a distance of twice Earth's radius from Earth's centre.
Given: Surface gravity = 10 m/s², Distance from centre = 2R

Outside a spherical Earth, gravitational acceleration varies inversely with the square of the distance from its centre.

g′ = g(R/r)²
  1. Substitute r = 2R.
  2. g′ = 10 × (R/2R)².
  3. g′ = 10 × 1/4.
Final Answer: g′ = 2.5 m/s²

Important: The distance here is measured from Earth's centre, not from the surface. Twice Earth's radius from the centre means an altitude of one Earth radius.

Question 18: Pressure in a Liquid

Calculate the pressure due to a water column at a depth of 1.5 metres. Take density of water = 1000 kg/m³ and g = 10 m/s².
Given: ρ = 1000 kg/m³, g = 10 m/s², h = 1.5 m
P = ρgh
  1. Write the water density as 1000 kg/m³.
  2. Multiply density, gravity and depth.
  3. 1000 × 10 × 1.5 = 15000.
Final Answer: Liquid Gauge Pressure = 15000 Pa

The answer represents pressure due to the water column. If absolute pressure is required, atmospheric pressure must also be included.

Question 19: Heat Required to Warm Water

How much heat is required to raise the temperature of 0.5 kg of water by 10°C? Take specific heat capacity of water as 4200 J/(kg·K). Assume no heat loss and no change of state.
Given: m = 0.5 kg, c = 4200 J/(kg·K), ΔT = 10 K
Q = mcΔT
Q = 0.5 × 4200 × 10
Q = 21000 J
Final Answer: Heat Required = 21000 J = 21 kJ

Remember: A temperature change of 10°C has the same numerical value as a temperature change of 10 K. This does not mean their zero points are the same.

Question 20: Speed of a Wave

A wave has a frequency of 15 Hz and wavelength of 2 metres. Calculate the wave speed.
Given: Frequency = 15 Hz, Wavelength = 2 m
Wave Speed = Frequency × Wavelength
v = fλ
v = 15 × 2 = 30 m/s
Final Answer: Wave Speed = 30 m/s

Frequency tells us how many complete oscillations occur per second. Wavelength is the distance between successive points in the same phase, such as two neighbouring crests.

Students preparing for NEET also need regular Physics practice along with Biology and Chemistry. For a wider preparation routine, see the NEET preparation roadmap and organise numerical practice around the chapters you have actually completed.

Class 11 Physics Numericals – Quick Answer Key

Use this table to revise all 20 numericals. Try to remember the formula before checking the answer.

Question Topic Final Answer
1Unit Conversion25 m/s
2Dimensions[MLT⁻²]
3Average Speed5 m/s
4Average Velocity2 m/s East
5Uniform Acceleration13 m/s, 40 m
6Braking5 s, 50 m
7Velocity-Time3 m/s², 32 m
8Vectors10 N
9Projectile Motion2 s, 5 m, 34.64 m
10Newton's Law15 N
11Friction20 N
12Impulse2 N·s
13Work60 J
14Kinetic Energy50 J
15Power30 W
16Torque6 N·m
17Gravitation2.5 m/s²
18Fluid Pressure15000 Pa
19Heat21000 J
20Waves30 m/s

Important Class 11 Physics Formulas for Beginners

This formula sheet brings together the main equations used in the solved examples. Learn what the symbols mean and where each formula can be applied.

Concept Formula
Average Speed Total distance / Total time
Average Velocity Displacement / Time interval
Acceleration a = (v − u)/t
Final Velocity v = u + at
Displacement s = ut + ½at²
Net Force F = ma
Kinetic Friction fₖ = μₖN
Impulse J = Δp
Work by Constant Force W = Fs cos θ
Kinetic Energy KE = ½mv²
Average Power P = W/t
Torque Magnitude τ = rF sin θ
Gravity Outside Earth g(r) = GM/r²
Fluid Gauge Pressure P = ρgh
Heat for Temperature Change Q = mcΔT
Wave Speed v = fλ
Formula tip: Do not apply formulas without checking their conditions. For example, v = u + at assumes constant acceleration, while Q = mcΔT is used for sensible heating or cooling without a phase change.

How to Practise Physics Numericals Without Getting Confused

The easiest way to improve numerical-solving skills is to practise a small number of questions carefully and understand every mistake. Solving many questions without checking the method is not always useful.

1. Understand the Formula Before Memorising It

Learn what the symbols mean and when the formula can be applied. For example, before using F = ma, understand that the force is the net external force responsible for acceleration.

2. Convert Units Before Calculation

A speed given in km/h should be converted to m/s when the rest of the question uses SI units. Similarly, grams may need to be converted into kilograms.

3. Draw Simple Diagrams for Motion and Forces

A small sketch can help you understand the direction of motion, friction or displacement. Make sure the directions are clear before assigning positive and negative signs.

4. Solve the Same Question Without Seeing the Answer

After reading a worked example, close the solution and solve it again. Then change one value and try a similar question on your own.

5. Maintain a Physics Mistake Notebook

Record whether a wrong answer came from a formula mistake, a calculation mistake or an incorrect unit. When you revise, focus on the types of errors that appear repeatedly.

6. Use Focused Practice Sessions

Numerical problems need concentration, especially when several steps are involved. If your study session becomes distracted, follow the techniques in our guide to studying without losing concentration . A focused session with five properly solved numericals is better than a long session of copied solutions.

A Simple 7-Day Physics Numerical Practice Plan

Beginners can use this plan to practise the main concepts gradually. Adjust the number of questions according to your current school syllabus.

Day 1 – Units

Practise SI unit conversion, dimensions and significant figures.

Day 2 – Motion

Solve speed, velocity and uniform acceleration questions.

Day 3 – Vectors

Learn basic components, resultant vectors and projectile motion.

Day 4 – Newton's Laws

Solve net force, friction and impulse problems.

Day 5 – Work and Energy

Practise work done, kinetic energy and power.

Day 6 – Other Chapters

Practise basic gravitation, fluid pressure, heat and waves.

Day 7 – Mixed Revision

Attempt ten mixed questions without referring to formulas. Review wrong answers afterwards.

Next Week – Repeat Weak Topics

Return to the formulas and concepts you found difficult. Gradually try more challenging questions.

If you are preparing for entrance examinations along with school studies, our self-study guide for competitive exams explains how to balance concept learning, practice and revision.

Common Mistakes in Class 11 Physics Numericals

  • Using the wrong formula: Read what the question asks before choosing an equation.
  • Ignoring SI units: Convert values before substitution where required.
  • Confusing distance and displacement: Check whether direction matters.
  • Forgetting negative signs: Define your positive direction in motion questions.
  • Skipping intermediate steps: Show the main substitution so calculations can be checked.
  • Forgetting squared values: Check expressions such as v² and t² carefully.
  • Mixing up mass and weight: Mass is measured in kg, while weight is a force measured in N.
  • Writing answers without units: A final numerical result should include the appropriate unit.

Test Your Understanding – 5 Quick Questions

Try solving these simple variations before opening the answers.

1. A body travels 150 m in 30 s. Find average speed.

Average speed = 150/30 = 5 m/s.

2. A 6 kg body accelerates at 2 m/s². Find the net force.

F = ma = 6 × 2 = 12 N.

3. Find the kinetic energy of a 2 kg body moving at 3 m/s.

KE = ½ × 2 × 3² = 9 J.

4. A machine performs 500 J of work in 10 s. Find average power.

P = 500/10 = 50 W.

5. A wave has frequency 5 Hz and wavelength 4 m. Find its speed.

v = fλ = 5 × 4 = 20 m/s.

Frequently Asked Questions

How do I start solving Class 11 Physics numericals?

Start with easy questions from Units and Measurements and Motion. Write the given values, convert units, choose the formula and solve each step carefully. Check the answer before moving to harder questions.

Which Class 11 Physics chapters have numericals?

Numericals appear across many chapters, including Units and Measurements, Kinematics, Laws of Motion, Work-Energy, Rotational Motion, Gravitation, Fluids, Thermal Physics, Oscillations and Waves.

Is Class 11 Physics difficult for beginners?

Physics may feel difficult initially because students encounter more mathematical concepts. Understanding formulas and practising simple examples regularly can make the subject easier.

How many Physics numericals should I practise daily?

There is no fixed number for everyone. Beginners can start with a small set of questions and focus on correct methods. Increase the number and difficulty as your understanding improves.

Are these 20 numericals official NCERT questions?

No. These are original practice examples based on common Class 11 Physics concepts. Students should also complete their prescribed NCERT textbook exercises and school assignments.

How can I remember Physics formulas?

Learn what each symbol means, practise the formula in different questions, create a small formula sheet and revisit the topic after a gap. Understanding helps you remember which formula is useful in a particular situation.

Conclusion

Class 11 Physics numericals become easier when you learn the method instead of memorising solved answers. Start with simple conversions, speed, velocity and acceleration before moving towards forces, energy and other chapters.

Practise one question at a time, understand why the formula works and always include the correct unit in your final answer. When a calculation goes wrong, check the mistake and try another question based on the same concept.

These 20 solved examples are a useful starting point for beginners. Continue with NCERT examples, textbook exercises and school-level practice to build a stronger understanding of Physics.

Keep your practice regular and focus on understanding each step. With time, even difficult Physics numericals can become much more manageable.

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